If you are still troubled for the Oracle 1Z0-853 certification exam, then select the IT-Tests.com's training materials please. IT-Tests.com's Oracle 1Z0-853 exam training materials is the best training materials, this is not doubt. Select it will be your best choice. It can guarantee you 100% pass the exam. Come on, you will be the next best IT experts.
The curtain of life stage may be opened at any time, the key is that you are willing to show, or choose to avoid. Most of People who can seize the opportunityin front of them are successful. So you have to seize this opportunity of IT-Tests.com. Only with it can you show your skills. IT-Tests.com Oracle 1Z0-218 exam training materials is the most effective way to pass the certification exam. With this certification, you will achieve your dreams, and become successful.
IT-Tests.com can not only save you valuable time, but also make you feel at ease to participate in the exam and pass it successfully. IT-Tests.com has good reliability and a high reputation in the IT professionals. You can free download the part of Oracle 1z1-061 exam questions and answers IT-Tests.com provide as an attempt to determine the reliability of our products. I believe you will be very satisfied of our products. I have confidence in our IT-Tests.com products that soon IT-Tests's exam questions and answers about Oracle 1z1-061 will be your choice and you will pass Oracle certification 1z1-061 exam successfully. It is wise to choose our IT-Tests.com and IT-Tests.com will prove to be the most satisfied product you want.
Why we are ahead of the other sites in the IT training industry? Because the information we provide have a wider coverage, higher quality, and the accuracy is also higher. So IT-Tests.com is not only the best choice for you to participate in the Oracle certification 1Z0-853 exam, but also the best protection for your success.
Exam Name: Java Standard Edition 5 Programmer Certified Professional Exam
Free One year updates to match real exam scenarios, 100% pass and refund Warranty.
1Z0-853 Test Answers Total Q&A: 362 Questions and Answers
Last Update: 2014-05-26
>> 1Z0-853 Real Exams detail
Exam Name: PeopleSoft HRMS Fundamentals
Free One year updates to match real exam scenarios, 100% pass and refund Warranty.
1Z0-218 Exam Dumps Total Q&A: 106 Questions and Answers
Last Update: 2014-05-26
>> 1Z0-218 Test Questions detail
Exam Name: Oracle Database 12c: SQL Fundamentals
Free One year updates to match real exam scenarios, 100% pass and refund Warranty.
1z1-061 Exam PDF Total Q&A: 75 Questions and Answers
Last Update: 2014-05-26
>> 1z1-061 Test Answers detail
IT-Tests's products can not only help customers 100% pass their first time to attend Oracle certification 1z1-061 exam, but also provide a one-year of free online update service for them, which will delivery the latest exam materials to customers at the first time to let them know the latest certification exam information. So IT-Tests.com is a very good website which not only provide good quality products, but also a good after-sales service.
1z1-061 (Oracle Database 12c: SQL Fundamentals) Free Demo Download: http://www.it-tests.com/1z1-061.html
NO.1 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C
Oracle test answers 1z1-061 PDF VCE 1z1-061 exam 1z1-061 exam dumps
NO.2 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C
Oracle Test Answers 1z1-061 1z1-061 1z1-061 answers real questions 1z1-061 pdf
NO.3 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail PA
B. Abigail Pa
C. Abigail IS
D. An error message
Answer: B
Oracle Study Guide 1z1-061 dumps torrent 1z1-061 practice test 1z1-061
NO.4 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D
Oracle Bootcamp 1z1-061 Bootcamp 1z1-061 Exam Prep
NO.5 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. DATE
B. NUMBER
C. TIMESTAMP
D. INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D
Oracle 1z1-061 1z1-061 questions 1z1-061 Practice Exam 1z1-061 Dumps PDF
NO.6 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B
Oracle 1z1-061 1z1-061 study guide 1z1-061 Practice Test
NO.7 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D
Oracle 1z1-061 Training online 1z1-061 1z1-061 1z1-061 Real Questions
NO.8 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C
Oracle practice test 1z1-061 1z1-061 Exam PDF 1z1-061 Exam Prep
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.
没有评论:
发表评论